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RESEARCH PRODUCT
Isotope Shift Measurements for Superdeformed Fission Isomeric States
M. HiesRoland RepnowBurkhard FrickeHartmut BackeO. CurtzeW. TheobaldH. KunzM. SewtzP. SchwambR. ZahnNorbert TrautmannKlaus EberhardtWerner LauthDietrich Habssubject
PhysicsIsotopeFissionResonance ionizationQuadrupoleGeneral Physics and AstronomyCharge (physics)Production (computer science)Atomic physicsdescription
Optical isotope shift measurements have been performed for the ${}^{240,242}{\mathrm{Am}}^{f}$ fission isomers with low target production rates of $10{\mathrm{s}}^{\ensuremath{-}1}$ employing resonance ionization spectroscopy in a buffer gas cell. Isotope shift ratios ${\mathrm{IS}}^{240f,241}/{\mathrm{IS}}^{243,241}\phantom{\rule{0ex}{0ex}}=\phantom{\rule{0ex}{0ex}}39.2(8)$ and ${\mathrm{IS}}^{242f,241}/{\mathrm{IS}}^{243,241}\phantom{\rule{0ex}{0ex}}=\phantom{\rule{0ex}{0ex}}41.4(8)$ have been measured at the 500.02 nm transition. A difference in the nuclear mean charge radii $\ensuremath{\delta}〈{r}^{2}{〉}_{\mathrm{opt}}^{242f,241}\phantom{\rule{0ex}{0ex}}=\phantom{\rule{0ex}{0ex}}5.34(28){\mathrm{fm}}^{2}$ and an intrinsic quadrupole moment ${Q}_{20}^{242f}\phantom{\rule{0ex}{0ex}}=\phantom{\rule{0ex}{0ex}}(35.5\ifmmode\pm\else\textpm\fi{}{1.0}_{\mathrm{st}}\ifmmode\pm\else\textpm\fi{}{1.2}_{\mathrm{mod}})e\mathrm{b}$ have been deduced, neglecting the nuclear polarization correction. The small difference $\ensuremath{\delta}{Q}_{20}^{242f,240f}\phantom{\rule{0ex}{0ex}}=\phantom{\rule{0ex}{0ex}}0.63(8)e\mathrm{b}$ demonstrates the stability of the deformation if two neutrons are removed.
year | journal | country | edition | language |
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1998-02-02 | Physical Review Letters |